Question

clyde and amelia both have heterozygous genotypes for color (yy).
clyde
amelia
phenotype probability (%)
yellow color:
blue color:

Explanation:

Step1: Complete the Punnett Square

Clyde and Amelia both have genotype \( Yy \). When we set up the Punnett Square, Clyde's alleles (Y and y) are on the top, and Amelia's alleles (Y and y) are on the side.

• Top - left cell: \( Y \) (Clyde) × \( Y \) (Amelia) = \( YY \)
• Top - right cell: \( Y \) (Clyde) × \( y \) (Amelia) = \( Yy \)
• Bottom - left cell: \( y \) (Clyde) × \( Y \) (Amelia) = \( Yy \)
• Bottom - right cell: \( y \) (Clyde) × \( y \) (Amelia) = \( yy \)

Step2: Determine Phenotypes

Assuming \( Y \) is dominant (yellow) and \( y \) is recessive (blue):

• Genotypes \( YY \), \( Yy \), \( Yy \) will show the yellow phenotype (3 out of 4 cells).
• Genotype \( yy \) will show the blue phenotype (1 out of 4 cells).

Step3: Calculate Probabilities

• Probability of yellow: \( \frac{3}{4} = 75\% \)
• Probability of blue: \( \frac{1}{4} = 25\% \)

Answer:

Yellow color: \( 75\% \)
Blue color: \( 25\% \)