Question

the class scores of a history test have a normal distribution with a mean \\(\mu = 79\\) and a standard deviation \\(\sigma = 7\\). if opals test score was 72, which expression would she write to find the z-score of her test score?

\\(z = \frac{72 - 79}{7}\\)

\\(z = \frac{72 - 7}{7}\\)

\\(z = \frac{79 - 72}{7}\\)

\\(z = \frac{7 - 79}{7}\\)

Explanation:

Identify the given parameters

Using the Z-Score Formula knowledge point

$$
LATEXBLOCK0
$$

Apply the formula

Using the Z-Score Formula knowledge point

$$ z = \frac{x - \mu}{\sigma} = \frac{72 - 79}{7} $$

Answer:

• (A) \(z = \frac{72 - 79}{7}\) (Correct answer)
• (B) \(z = \frac{72 - 7}{7}\)
• (C) \(z = \frac{79 - 72}{7}\)
• (D) \(z = \frac{7 - 79}{7}\)