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at a certain pizza parlor, 65% of the customers order a pizza containin…

Question

at a certain pizza parlor, 65% of the customers order a pizza containing onions, 40% of the customers order a pizza containing sausage, and 78% order a pizza containing onions or sausage (or both). find the probability that a customer chosen at random will order a pizza containing both onions and sausage.

write your answer as a decimal (not as a percentage). (if necessary, consult a list of formulas.)

Explanation:

Define the events and given probabilities

Using the Probability of Events knowledge point

$$ LATEXBLOCK0 $$

Apply the Addition Rule of Probability

We want to find the probability of the intersection, \(P(O \cap S)\).

$$ P(O \cup S) = P(O) + P(S) - P(O \cap S) $$

Solve for the intersection probability

$$ LATEXBLOCK1 $$

Answer:

At a certain pizza parlor, 65% of the customers order a pizza containing onions, 40% of the customers order a pizza containing sausage, and 78% order a pizza containing onions or sausage (or both). Find the probability that a customer chosen at random will order a pizza containing both onions and sausage.

Write your answer as a decimal (not as a percentage).

<blank>0.27</blank>