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a catapult launches a rock 5 different times with the following distanc…

Question

a catapult launches a rock 5 different times with the following distances: 26 cm, 30 cm, 35 cm, 40 cm, 37 cm. what is the average distance the catapult launched the rock? ______ cm

Explanation:

Step1: Sum the distances

To find the average, first sum all the distances. The distances are 26 cm, 30 cm, 35 cm, 40 cm, and 37 cm. So, we calculate \(26 + 30 + 35 + 40 + 37\). Let's add them step by step: \(26+30 = 56\), \(56 + 35 = 91\), \(91 + 40 = 131\), \(131 + 37 = 168\).

Step2: Divide by the number of trials

There are 5 trials. The formula for the average (mean) is \(\frac{\text{Sum of values}}{\text{Number of values}}\). So we divide the sum (168) by 5: \(\frac{168}{5}=33.6\).

Answer:

33.6