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Question
- calculate each of the following sums and then use front-end estimation to the reasonableness of your answer. (a) 13.1 + 2.4 = ____ estimation check: __ (b) 4.52 + 3.09 = __ estimation check: __ (c) 3.51 + 9.73 = __ estimation check: __ (d) 2.168 + 0.948 = __ estimation check: ____
Part (a)
Step 1: Calculate the sum
To find \(13.1 + 2.4\), we add the decimal numbers:
Step 2: Front - end estimation
Front - end estimation means we use the leading digits. For \(13.1\), the front - end digit is \(13\) (we can consider the whole number part), and for \(2.4\), the front - end digit is \(2\). Then \(13 + 2=15\). The actual sum \(15.5\) is close to \(15\), so the answer is reasonable.
Part (b)
Step 1: Calculate the sum
To find \(4.52+3.09\), we add the decimal numbers:
Step 2: Front - end estimation
For \(4.52\), the front - end digit (whole number part) is \(4\), and for \(3.09\), the front - end digit is \(3\). Then \(4 + 3 = 7\). The actual sum \(7.61\) is close to \(7\), so the answer is reasonable.
Part (c)
Step 1: Calculate the sum
To find \(3.51+9.73\), we add the decimal numbers:
Step 2: Front - end estimation
For \(3.51\), the front - end digit (whole number part) is \(3\), and for \(9.73\), the front - end digit is \(9\). Then \(3+9 = 12\). The actual sum \(13.24\) is close to \(12\), so the answer is reasonable.
Part (d)
Step 1: Calculate the sum
To find \(2.168+0.948\), we add the decimal numbers:
Step 2: Front - end estimation
For \(2.168\), the front - end digit (whole number part) is \(2\), and for \(0.948\), the front - end digit is \(0\) (or we can consider \(1\) since \(0.948\) is close to \(1\)). If we take \(2 + 1=3\). The actual sum \(3.116\) is close to \(3\), so the answer is reasonable.
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(a) Sum: \(15.5\), Estimation check: \(13 + 2=15\) (close to \(15.5\))
(b) Sum: \(7.61\), Estimation check: \(4+3 = 7\) (close to \(7.61\))
(c) Sum: \(13.24\), Estimation check: \(3 + 9=12\) (close to \(13.24\))
(d) Sum: \(3.116\), Estimation check: \(2+1 = 3\) (close to \(3.116\))