Question

1. a brown - eyed homozygous dominant female (bb) has a baby with a brown - eyed heterozygous male (bb). b = brown, b = blue

genotype
phenotype
possibility 1:
possibility 2:
possibility 3:
possibility 4:

Explanation:

Step1: Determine the gametes

The homozygous dominant female (BB) can only produce gametes with the allele B. The heterozygous male (Bb) can produce gametes with alleles B and b.

Step2: Fill in the Punnett square

	B	B
b	Bb	Possibility 2: Bb
		Possibility 3: BB
		Possibility 4: Bb

For genotype:

• Possibility 1: BB
• Possibility 2: Bb
• Possibility 3: BB
• Possibility 4: Bb

Since B (brown) is dominant over b (blue), for phenotype:

• BB and Bb both result in brown - eyed. So all possibilities (1 - 4) have the phenotype of brown - eyed.

Answer:

Genotype:
Possibility 1: BB
Possibility 2: Bb
Possibility 3: BB
Possibility 4: Bb
Phenotype:
Possibility 1: Brown - eyed
Possibility 2: Brown - eyed
Possibility 3: Brown - eyed
Possibility 4: Brown - eyed