Question

based on mendels pea plant punnett square crosses, what will be the probability that a pea plant will be wrinkled if a homozygous dominant round plant and a homozygous recessive wrinkled plant are crossed? parent 1 rr parent 2 rr 75% 0% 100% 50%

Explanation:

Step1: Determine Genotypes of Gametes

Parent 1 (RR) can only produce gametes with the allele R. Parent 2 (rr) can only produce gametes with the allele r.

Step2: Create Punnett Square

When we cross RR and rr, the Punnett Square will have all offspring with the genotype Rr.

Step3: Determine Phenotype Probability

The allele for round (R) is dominant over wrinkled (r). So, all offspring with Rr genotype will have the round phenotype. Thus, the probability of a wrinkled (rr) plant is 0%.

Answer:

0%