Question

a bag was filled with colored items. felicia repeatedly drew one at random, then replaced it. she did this 14 times. here are the results: colored item experiment | color | times | | blue | 3 | | pink | 2 | | green | 4 | | yellow | 5 | what is the experimental probability of not drawing a pink or a yellow item? write your answer as a fraction.

Explanation:

Step1: Find total trials

Total trials = 3 (blue) + 2 (pink) + 4 (green) + 5 (yellow) = 14.

Step2: Find trials of pink or yellow

Trials of pink or yellow = 2 + 5 = 7.

Step3: Find trials of NOT pink or yellow

Trials of NOT pink or yellow = Total - Trials of pink or yellow = 14 - 7 = 7.

Step4: Calculate probability

Probability = $\frac{\text{Trials of NOT pink or yellow}}{\text{Total trials}}$ = $\frac{7}{14}$ = $\frac{1}{2}$. Wait, no, wait: Wait, 3 (blue) + 4 (green) = 7. So 7/14 simplifies to 1/2? Wait, no, let's recalculate. Wait, total trials: 3 + 2 + 4 + 5 = 14. Trials of pink: 2, yellow: 5. So trials of pink or yellow: 2 + 5 = 7. So trials of NOT pink or yellow: 14 - 7 = 7. So probability is 7/14 = 1/2? Wait, but blue is 3, green is 4, 3 + 4 = 7. So yes, 7/14 = 1/2. Wait, but let's check again. Blue: 3, pink: 2, green: 4, yellow: 5. Total: 3+2=5, 5+4=9, 9+5=14. Correct. Pink or yellow: 2+5=7. So not pink or yellow: 14-7=7. So probability is 7/14 = 1/2. Wait, but maybe I made a mistake. Wait, the question is "NOT drawing a pink or a yellow item". So pink and yellow are the ones we don't want? No, wait: "NOT drawing a pink or a yellow item" means drawing blue or green. So blue (3) + green (4) = 7. Total trials 14. So 7/14 = 1/2. Yes.

Answer:

$\frac{7}{14}$ (or simplified to $\frac{1}{2}$)