Question

a bag contains 6 red, 5 green, and 7 blue marbles. one marble is drawn at random. what is the probability that the marble is not green?

\\(p(\text{not green}) = \quad\\%\\)

round your answer to the nearest whole percent.

Explanation:

Calculate total number of marbles

$$ \text{Total} = 6 + 5 + 7 = 18 $$

Determine number of non-green marbles

$$ \text{Not Green} = 6 \text{ (red)} + 7 \text{ (blue)} = 13 $$

Calculate and round the probability

$$ P(\text{not green}) = \frac{13}{18} \approx 0.7222 \approx 72\% $$

Answer:

A bag contains 6 red, 5 green, and 7 blue marbles. One marble is drawn at random. What is the probability that the marble is not green?

\(P(\text{not green}) =\) <blank>72</blank>%