Question

a bag contains four red marbles, three yellow marbles, and three purple marbles. you will randomly select one marble from the bag. which statements are true regarding the scenario? check all that apply. the probability you select a red marble is \frac{3}{10}. the probability you select a purple marble is \frac{3}{10}. p(red) + p(yellow) + p(purple) = 1 the probability you select a green marble is 0. the probability you select a yellow marble is 3.

Explanation:

Step1: Calculate total number of marbles

Total marbles = \(4 + 3+3=10\)

Step2: Calculate probability of red marble

\(P(\text{Red})=\frac{4}{10}
eq\frac{3}{10}\)

Step3: Calculate probability of purple marble

\(P(\text{Purple})=\frac{3}{10}\)

Step4: Check sum of probabilities

\(P(\text{Red})+P(\text{Yellow})+P(\text{Purple})=\frac{4}{10}+\frac{3}{10}+\frac{3}{10}=\frac{4 + 3+3}{10}=1\)

Step5: Check probability of green marble

Since there are no green marbles, \(P(\text{Green}) = 0\)

Step6: Check probability of yellow marble

\(P(\text{Yellow})=\frac{3}{10}
eq3\)

Answer:

• The probability you select a purple marble is \(\frac{3}{10}\).
• \(P(\text{Red})+P(\text{Yellow})+P(\text{Purple}) = 1\)
• The probability you select a green marble is \(0\).