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assume that a procedure yields a binomial distribution with n = 6 trial…

Question

assume that a procedure yields a binomial distribution with n = 6 trials and a probability of success of p = 0.80. use a binomial probability table to find the probability that the number of successes x is exactly 3. click on the icon to view the binomial probabilities table. p(3) = □ (round to three decimal places as needed.)

Explanation:

Step1: Locate the row for \(n = 6\)

In the binomial probabilities table, find the section where the number of trials \(n=6\).

Step2: Locate the column for \(p = 0.80\)

In the \(n = 6\) section, find the column corresponding to the probability of success \(p = 0.80\).

Step3: Locate the value for \(x = 3\)

In the intersection of the row for \(n = 6\), column for \(p = 0.80\), and the row within that sub - table for \(x = 3\).

Answer:

\(0.082\)