Question

assume that different groups of couples use a particular method of gender selection and each couple gives birth to one baby. this method is designed to increase the likelihood that each baby will be a girl, but assume that the method has no effect, so the probability of a girl is 0.5. assume that the groups consist of 18 couples. complete parts (a) through (c) below.
a. find the mean and the standard deviation for the numbers of girls in groups of 18 births.
the value of the mean is \\( \mu = 9 \\).
(type an integer or a decimal. do not round.)
the value of the standard deviation is \\( \sigma = 2.1 \\).
(round to one decimal place as needed)
b. use the range rule of thumb to find the values separating results that are significantly low or significantly high.
values of 4.8 girls or fewer are significantly low.
(round to one decimal place as needed.)
values of \\( \square \\) girls or greater are significantly high.
(round to one decimal place as needed.)

Explanation:

Step1: Recall the range rule of thumb formula

The range rule of thumb states that values are significantly low if they are less than or equal to \(\mu - 2\sigma\) and significantly high if they are greater than or equal to \(\mu+ 2\sigma\). We know \(\mu = 9\) and \(\sigma=2.1\) from part (a).

Step2: Calculate the value for significantly high

We use the formula \(x=\mu + 2\sigma\). Substitute \(\mu = 9\) and \(\sigma = 2.1\) into the formula: \(x=9+2\times2.1\).
First, calculate \(2\times2.1 = 4.2\). Then \(9 + 4.2=13.2\).

Answer:

\(13.2\)