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4. in another one of mendels experiments, he crossed the offspring. two…

Question

  1. in another one of mendels experiments, he crossed the offspring. two pea plants with purple flowers (pp) were crossed. purple flowers purple flowers p p genotype probability (%) phenotype probability (%) pp 0% purple flowers: 0% pp 0% white flowers: 0% pp 0%

Explanation:

Step1: Fill in the Punnett square

The Punnett square for \(Pp\times Pp\) is:

\(P\)\(p\)
\(p\)\(Pp\)\(pp\)

Step2: Calculate genotype probabilities

There are 4 possible outcomes.

  • For \(PP\): There is 1 out of 4, so the probability is \(\frac{1}{4}=25\%\)
  • For \(Pp\): There are 2 out of 4, so the probability is \(\frac{2}{4} = 50\%\)
  • For \(pp\): There is 1 out of 4, so the probability is \(\frac{1}{4}=25\%\)

Step3: Calculate phenotype probabilities

Since \(P\) (purple) is dominant over \(p\) (white).

  • \(PP\) and \(Pp\) show purple flowers. There are \(1 + 2=3\) out of 4, so the probability of purple flowers is \(\frac{3}{4}=75\%\)
  • \(pp\) shows white flowers. There is 1 out of 4, so the probability of white flowers is \(\frac{1}{4}=25\%\)

Answer:

Genotype Probability (\%):

  • \(PP\): \(25\%\)
  • \(Pp\): \(50\%\)
  • \(pp\): \(25\%\)

Phenotype Probability (\%):

  • Purple Flowers: \(75\%\)
  • White Flowers: \(25\%\)