Question

amount of money
0 ≤ y ≤ 30
40 ≤ x ≤ 100
0 ≤ x ≤ 30
40 ≤ y ≤ 100

Explanation:

Step1: Identify the axes

The x - axis is "Number of People" and the y - axis is "Amount of Money".

Step2: Determine the range of y

Looking at the graph, the line starts at \(y = 40\) and goes up to \(y=180\) (approximate upper - limit shown in the graph). Among the options, \(40\leq y\leq100\) is incorrect as the upper - value in the graph is higher than 100. \(0\leq y\leq30\) is wrong since the line starts at \(y = 40\). For the x - axis, if we consider the domain of the line (assuming it's a function \(y=f(x)\)), the line starts at \(x = 0\) (since when \(x = 0\), \(y=40\)) and goes to \(x = 90\) (approximate). \(40\leq x\leq100\) is wrong as \(x\) starts at 0. \(0\leq x\leq30\) is wrong as the line extends beyond \(x = 30\). But if we assume there was a mis - labeling in options (maybe a typo in the problem's options and we focus on the y - axis range conceptually closest among the given options, and check the y - values):
The line has a y - intercept at \(y = 40\) and the y - values go upwards. If we consider the options for the range of \(y\) (assuming the options are mis - numbered or mis - written in terms of variable correspondence in a basic range - determination from the graph), the line starts at \(y = 40\) (lower bound) and the upper - bound in the options \(40\leq y\leq100\) is the only one that has the correct lower - bound for \(y\) among the given options (even though the graph's upper \(y\) is higher, but if we consider the closest in terms of variable assignment (assuming \(y\) is the amount of money which starts at 40)).

Answer:

\(40\leq y\leq100\)