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9. the amount a couple spends on average for food (eating out and cooki…

Question

  1. the amount a couple spends on average for food (eating out and cooking) is $553 per month with a standard deviation of $50. find a couples a score if they spend $510 per month. determine the percentage of couples who spent less than $510 and draw the normal curve.

z score:____ percentage of $510 or less spent:____

  1. during the 2022 nfl season, the average yards by throwing was 223 yards with a standard deviation of 18. if one quarterback threw for 258 yards, what was his score? what percentage was 258 yards or less? what percentage was more than 258 yards. draw the normal curve and label where 258 yards would be.

z score:____ percentage of 258 yards or less:__ percentage of more than 258 yards:____

  1. on average the weather in death valley, california averages 119 degrees fahrenheit during the month of july. the standard deviation is 3.8 degrees.

a. what percentage days were 118 degrees or less?
b. what percentage of days were 125 degrees or more?
c. what percent of days was the weather between 118 and 125 degrees in july?

  1. beaches resorts are family vacation destinations in the caribbean. on average if you go to turks and caicos beaches the average family price is $4,320 with a standard deviation of $350. if you go to antigua beaches, the average family price is $5,600 with a standard deviation of $600. the garcia family went to turks and calcos and spent $4,800. the rodriguez family went to antigua and spent $5,500. explain who received a better deal.

Explanation:

Step1: Calculate the z - score

The formula for the z - score is \(z=\frac{x-\mu}{\sigma}\), where \(x = 510\), \(\mu=553\), and \(\sigma = 50\).

$$z=\frac{510 - 553}{50}=\frac{-43}{50}=- 0.86$$

Step2: Find the percentage using the z - table

Looking up \(z=-0.86\) in the standard normal table (z - table). The value corresponding to \(z =-0.86\) is \(0.1949\) or \(19.49\%\)

Answer:

Z score: \(-0.86\)
Percentage of \(\$510\) or less spent: \(19.49\%\)