Question

algebra 2 with probability ic bchs summer
probability

a man owns five bow ties. he chooses one bow tie at random to wear on any given day. the polka-dot bow tie is his favorite, so his random process uses a larger probability for that bow tie. the rest of the bow ties are given equal probabilities of being chosen, as shown in the table.

\

$$\begin{tabular}{|c|c|c|c|c|} \\hline polka dot & stripes & checkered & argyle & paisley \\\\ \\hline 0.40 & ? & ? & ? & ? \\\\ \\hline \\end{tabular}$$

what is the value of the missing probabilities?

• 0.60
• 0.25
• 0.20
• 0.15

Explanation:

Sum of all probabilities in a sample space

$$ P(\text{Polka Dot}) + P(\text{Stripes}) + P(\text{Checkered}) + P(\text{Argyle}) + P(\text{Paisley}) = 1 $$

Set up equation for the remaining equal probabilities

$$
LATEXBLOCK0
$$

Solve for the missing probability

$$
LATEXBLOCK1
$$

Answer:

• 0.60
• 0.25
• 0.20
• 0.15 (Correct answer)