Question

the accompanying data table contains chest deceleration measurements (in g, where g is the force of gravity) from samples of small, midsize, and large cars. shown are the technology results for analysis of variance of this data table. assume that a researcher plans to use a 0.05 significance level to test the claim that the different size categories have the same mean chest deceleration in the standard crash test. complete parts (a) and (b) below. click the icon to view the table of chest deceleration measurements click the icon to view the table of analysis of variance results. b. the measurements are categorized according to the one characteristic of size. c. there are three samples of measurements. d. nothing specifically indicates that one - way analysis of variance should be used. b. if the objective is to test the claim that the three size categories have the same mean chest deceleration, why is the method referred to as analysis of variance? a. the method is based on estimates of a common population variance. b. the method is based on estimates of multiple varying population variances. c. the method is based on showing that the population variances are similar. d. the method is based on showing that the population variances are different.

Explanation:

Analysis of variance (ANOVA) is used to test the equality of means. The key idea is that it estimates a common population variance. By comparing the variance between groups and within groups, we can determine if the means are equal. If the variance between groups is significantly larger than the variance within groups (based on estimates of the common population variance), we reject the claim of equal means.

Answer:

A. The method is based on estimates of a common population variance.