Question

of the 49 plays attributed to a playwright, 17 are comedies, 19 are tragedies, and 13 are histories. if one play is selected at random, find the odds in favor of selecting a history. the odds in favor of selecting a history are \\(\square: \square\\). (simplify your answer.)

Explanation:

Step1: Calculate the number of non - history plays

The total number of plays is \(n = 49\), and the number of history plays is \(n_{history}=13\). The number of non - history plays is \(n_{non - history}=49 - 13=36\).

Step2: Calculate the odds in favor

The odds in favor of an event \(E\) (in this case, \(E\) is selecting a history play) is given by the formula \(\text{Odds in favor}=\frac{\text{Number of favorable outcomes}}{\text{Number of unfavorable outcomes}}\).
So, the odds in favor of selecting a history play is \(\frac{13}{36}\).

Answer:

\(13:36\)