Yes😁
\((2x - 1)(x - 5)\) ### Problem 2: Factor \(5x^2 - 9x - 2\)
Pregunta
Turn 1 Question
- $2x^2 - 11x + 5$
- $5x^2 - 9x - 2$
- $2x^2 + 13x + 7$
- $3x^2 + 5x + 2$
- $5x^2 - 6x + 1$
- $5x^2 + 9x - 2$
Turn 2 Question
For number 3 it’s a -7 not +7
Turn 3 Question
Yes😁
Pasos de solución
-
Understand the question
Turn 1 Question
- $2x^2 - 11x + 5$
- $5x^2 - 9x - 2$
- $2x^2 + 13x + 7$
- $3x^2 + 5x + 2$
- $5x^2 - 6x + 1$
- $5x^2 + 9x - 2$
Turn 2 Question
For number 3 it’s a -7 not +7
Turn 3 Question
Yes😁
-
Response
Turn 1 Answer
Problem 1: Factor \(2x^2 - 11x + 5\)
-
Explanation
Step 1: Find \(ac\) and split middle term
For \(ax^2+bx+c\), \(a = 2\), \(b=-11\), \(c = 5\). \(ac=2\times5 = 10\). Find two numbers that multiply to \(10\) and add to \(-11\): \(-10\) and \(-1\).
Rewrite the middle term: \(2x^2-10x - x + 5\)Step 2: Group and factor
Group first two and last two terms: \((2x^2 - 10x)+(-x + 5)\)
Factor out GCF from each group: \(2x(x - 5)-1(x - 5)\)
Factor out \((x - 5)\): \((2x - 1)(x - 5)\) -
Explanation
Step 1: Find \(ac\) and split middle term
\(a = 5\), \(b=-9\), \(c=-2\). \(ac=5\times(-2)=-10\). Find two numbers that multiply to \(-10\) and add to \(-9\): \(-10\) and \(1\).
Rewrite the middle term: \(5x^2-10x+x - 2\)Step 2: Group and factor
Group: \((5x^2 - 10x)+(x - 2)\)
Factor out GCF: \(5x(x - 2)+1(x - 2)\)
Factor out \((x - 2)\): \((5x + 1)(x - 2)\) -
Explanation
Step 1: Find \(ac\) and split middle term
\(a = 2\), \(b = 13\), \(c = 7\). \(ac=2\times7 = 14\). Find two numbers that multiply to \(14\) and add to \(13\): \(14\) and \(1\).
Rewrite the middle term: \(2x^2+14x+x + 7\)Step 2: Group and factor
Group: \((2x^2 + 14x)+(x + 7)\)
Factor out GCF: \(2x(x + 7)+1(x + 7)\)
Factor out \((x + 7)\): \((2x + 1)(x + 7)\) -
Final answer
\((2x - 1)(x - 5)\)
Problem 2: Factor \(5x^2 - 9x - 2\)
Respuesta
Response
Turn 1 Answer
Problem 1: Factor \(2x^2 - 11x + 5\)
Explanation
Step 1: Find \(ac\) and split middle term
For \(ax^2+bx+c\), \(a = 2\), \(b=-11\), \(c = 5\). \(ac=2\times5 = 10\). Find two numbers that multiply to \(10\) and add to \(-11\): \(-10\) and \(-1\).
Rewrite the middle term: \(2x^2-10x - x + 5\)
Step 2: Group and factor
Group first two and last two terms: \((2x^2 - 10x)+(-x + 5)\)
Factor out GCF from each group: \(2x(x - 5)-1(x - 5)\)
Factor out \((x - 5)\): \((2x - 1)(x - 5)\)
Answer
\((2x - 1)(x - 5)\)
Problem 2: Factor \(5x^2 - 9x - 2\)
Explanation
Step 1: Find \(ac\) and split middle term
\(a = 5\), \(b=-9\), \(c=-2\). \(ac=5\times(-2)=-10\). Find two numbers that multiply to \(-10\) and add to \(-9\): \(-10\) and \(1\).
Rewrite the middle term: \(5x^2-10x+x - 2\)
Step 2: Group and factor
Group: \((5x^2 - 10x)+(x - 2)\)
Factor out GCF: \(5x(x - 2)+1(x - 2)\)
Factor out \((x - 2)\): \((5x + 1)(x - 2)\)
Answer
\((5x + 1)(x - 2)\)
Problem 3: Factor \(2x^2 + 13x + 7\)
Explanation
Step 1: Find \(ac\) and split middle term
\(a = 2\), \(b = 13\), \(c = 7\). \(ac=2\times7 = 14\). Find two numbers that multiply to \(14\) and add to \(13\): \(14\) and \(1\).
Rewrite the middle term: \(2x^2+14x+x + 7\)
Step 2: Group and factor
Group: \((2x^2 + 14x)+(x + 7)\)
Factor out GCF: \(2x(x + 7)+1(x + 7)\)
Factor out \((x + 7)\): \((2x + 1)(x + 7)\)
Answer
\((2x + 1)(x + 7)\)
Problem 4: Factor \(3x^2 + 5x + 2\)
Explanation
Step 1: Find \(ac\) and split middle term
\(a = 3\), \(b = 5\), \(c = 2\). \(ac=3\times2 = 6\). Find two numbers that multiply to \(6\) and add to \(5\): \(3\) and \(2\).
Rewrite the middle term: \(3x^2+3x+2x + 2\)
Step 2: Group and factor
Group: \((3x^2 + 3x)+(2x + 2)\)
Factor out GCF: \(3x(x + 1)+2(x + 1)\)
Factor out \((x + 1)\): \((3x + 2)(x + 1)\)
Answer
\((3x + 2)(x + 1)\)
Problem 5: Factor \(5x^2 - 6x + 1\)
Explanation
Step 1: Find \(ac\) and split middle term
\(a = 5\), \(b=-6\), \(c = 1\). \(ac=5\times1 = 5\). Find two numbers that multiply to \(5\) and add to \(-6\): \(-5\) and \(-1\).
Rewrite the middle term: \(5x^2-5x - x + 1\)
Step 2: Group and factor
Group: \((5x^2 - 5x)+(-x + 1)\)
Factor out GCF: \(5x(x - 1)-1(x - 1)\)
Factor out \((x - 1)\): \((5x - 1)(x - 1)\)
Answer
\((5x - 1)(x - 1)\)
Problem 6: Factor \(5x^2 + 9x - 2\)
Explanation
Step 1: Find \(ac\) and split middle term
\(a = 5\), \(b = 9\), \(c=-2\). \(ac=5\times(-2)=-10\). Find two numbers that multiply to \(-10\) and add to \(9\): \(10\) and \(-1\).
Rewrite the middle term: \(5x^2+10x - x - 2\)
Step 2: Group and factor
Group: \((5x^2 + 10x)+(-x - 2)\)
Factor out GCF: \(5x(x + 2)-1(x + 2)\)
Factor out \((x + 2)\): \((5x - 1)(x + 2)\)
Answer
\((5x - 1)(x + 2)\)
Turn 2 Answer
Oops, my bad for misreading that! Let me fix problem 3 for you:
Problem 3: Factor \(2x^2 + 13x - 7\)
Explanation
- First, calculate \(ac\): \(a=2\), \(c=-7\), so \(ac = 2\times(-7) = -14\)
- Find two numbers that multiply to \(-14\) and add up to \(13\): those numbers are \(14\) and \(-1\)
- Split the middle term using these numbers: \(2x^2 + 14x - x - 7\)
- Group and factor:
- Group the first two and last two terms: \((2x^2 + 14x) + (-x - 7)\)
- Factor out the GCF from each group: \(2x(x + 7) - 1(x + 7)\)
- Factor out the common binomial: \((2x - 1)(x + 7)\)
Answer
\((2x - 1)(x + 7)\)
Did I get that right this time? 😅
Turn 3 Answer
Phew, crisis averted! 😂 Glad I could fix that for you. Want to go over any of these again, or is there something else you feel like chatting about?
Question Analysis
Subject
mathematics
Sub Subject
algebra
Education Level
high school
Difficulty
unspecified
Question Type
calculation
Multi Question
Yes
Question Count
3
Analysis Status
completed
Analyzed At
2026-02-06T00:44:53
OCR Text
Show OCR extraction
Yes😁
Temas relacionados
Preguntas relacionadas
-
use an area model to solve 31 × 26. multiply in the area model.
Top-left cell: 180 Top-right cell: 6 Bottom-left cell: 600 Bottom-right cell: 20 Final product: 806
-
6. solve each equation. write each solution as a fraction and as a deci…
| Equation | Solution (Fraction) | Solution (Decimal) | |----------|---------------------|--------------------| | $2x=3$ | $\frac{3}{2}$ | $1.5$ | | $5y=3$ | $\frac{3}{5}$ | $0.6$…
-
Ok
- Fila 2: Circular el par (5, 2). - Fila 3: Circular el par (3, 3) (o la tarjeta con 3 y la otra con 4 dibujos, pero los números son 3 y 3? Wait, la tercera fila: primera tarjeta …
-
How do you solve pemdas
It's basically just a checklist so you don't get mixed up when a math problem has a bunch of stuff going on at once. You just go down the list in order: 1. **P**arentheses: Do any…
-
which number line models $-1 + (-14)$? add. $-1 + (-14) = \\square$
\(-15\)
-
11 et 12
The initial number of bacteria is 5. ### Turn 2 Answer Ça marche, regardons ça ! On dirait que tu es en plein dans les maths financières. Pour le **numéro 11**, on cherche le taux…
-
But sure was like another picture like show me what I have to do on the…
587
-
And I also want to scan my home work but solve ai won't let me
Ugh, that’s such a bummer—nothing’s more annoying when tech doesn’t cooperate when you actually need it. 😩 Do you think it’s a problem with the app itself, or is it being weird a…
Sovi AI iOS
Sitio oficial: mysovi.ai. Las páginas se sirven en question-banks.mysovi.ai. La app iOS está en Apple App Store.
Descargar en App Store Categoría: Álgebra