Question

1. a cell store sells iphones and droids. the store makes a $40 profit on each iphone (i) and $55 profit on each droid (d). the store wants to make a profit of at least $375 each day from cell phone sales. which inequality describes this situation?

a. 40i + 55d < 375
b. 40i + 55d > 375
c. 40i + 55d ≤ 375
d. 40i + 55d ≥ 375

1. mr. lawes wrote eight less than three times a number is more than fifteen on the board. if x represents the number, which inequality is a correct translation of this statement?

a. 3x - 8 > 15
b. 3x - 8 < 15
c. 8 - 3x > 15
d. 8 - 3x < 15

1. what is the greatest whole number, x, for which 3x < 11?

a. 33
b. 34
c. 3
d. 4

Explanation:

18)

Step1: Calculate total profit

Profit from iPhones is \(40I\) (since each iPhone gives \(\$40\) profit and there are \(I\) iPhones). Profit from Droid is \(55d\) (since each Droid gives \(\$55\) profit and there are \(d\) Droids). Total profit is \(40I + 55d\).

Step2: Interpret the profit requirement

The store wants to make a profit of at least \(\$375\). “At least” means greater than or equal to. So the inequality is \(40I+55d\geq375\).

Step1: Translate “three times a number”

If \(x\) is the number, three times the number is \(3x\).

Step2: Translate “eight less than three times a number”

Eight less than \(3x\) is \(3x - 8\).

Step3: Translate “is more than fifteen”

“Is more than” means \(>\). So the inequality is \(3x-8 > 15\).

Step1: Solve the inequality \(3x<11\)

Divide both sides of the inequality \(3x < 11\) by \(3\). We get \(x<\frac{11}{3}\approx3.67\).

Step2: Find the greatest whole - number

The greatest whole number less than \(3.67\) is \(3\).

Answer:

d. \(40I + 55d\geq375\)

19)