Question

1. if we flip a coin eight times, how many possible sequences of eight coin faces (i.e., heads or tails) can we have?

1,024
2,048
512
256

Explanation:

Step1: Identify the number of choices per flip

A coin has 2 possible outcomes (heads or tails) for each flip.

Step2: Apply the multiplication principle

For 8 flips, the total number of sequences is $2^8$ (since each flip is an independent event with 2 choices).
Calculate $2^8$: $2\times2\times2\times2\times2\times2\times2\times2 = 256$.

Answer:

256 (corresponding to the option "256")