Question

1. how do you calculate the probability of two independent events happening consecutively, such as flipping heads then rolling a 6?

a. multiply the probability of each event
b. divide the probability of one event by the other
c. add the probability of each event
d. subtract the probability of one event from the other

Explanation:

For two independent events \(A\) and \(B\), the probability of both \(A\) and \(B\) occurring is given by the formula \(P(A\cap B)=P(A)\times P(B)\). In the example of flipping heads (probability \(P(\text{heads})=\frac{1}{2}\)) and then rolling a \(6\) (probability \(P(6)=\frac{1}{6}\)), the combined probability is \(\frac{1}{2}\times\frac{1}{6}\). This follows the rule of multiplying the probabilities of independent events. Dividing (\(b\)), adding (\(c\)), or subtracting (\(d\)) the probabilities of independent events is not the correct approach for finding the probability of both events happening consecutively.

Answer:

A. Multiply the probability of each event