Question

1. using the trait of \free earlobes\ (e) and \attached earlobes\ (e), design your own punnett square. make you father heterozygous and your mother homozygous recessive. what is the probability of the child having attached earlobes?______

Explanation:

Step1: Determine parents' genotypes

Father is heterozygous: \(Ee\). Mother is homozygous recessive: \(ee\).

Step2: Set up Punnett square

Father's gametes: \(E\) and \(e\). Mother's gametes: \(e\) and \(e\).

$$\begin{array}{|c|c|c|} \hline & E & e \\ \hline e & Ee & ee \\ \hline e & Ee & ee \\ \hline \end{array}$$

Step3: Calculate probability

There are 4 possible offspring genotypes. 2 of them (\(ee\)) result in attached earlobes. Probability \(=\frac{2}{4}=\frac{1}{2} = 50\%\)

Answer:

The probability of the child having attached earlobes is \(50\%\)