Question

1. in rabbits, black fur (b) is dominant to white fur (b). a purebred (homozygous) black - furred male is bred with a female that has the recessive white fur.

black fur
phenotype
probability (%)
black fur: 100%
white fur: 0%

Explanation:

Step1: Determine the genotypes

The purebred (homozygous) black - furred male has the genotype \( BB \), and the recessive white - furred female has the genotype \( bb \).

Step2: Create the Punnett square

When we cross \( BB \) (male) with \( bb \) (female), the male can only contribute \( B \) gametes, and the female can only contribute \( b \) gametes. So the Punnett square will have all offspring with the genotype \( Bb \).

Step3: Determine the phenotype

Since \( B \) (black fur) is dominant over \( b \) (white fur), all offspring with the genotype \( Bb \) will have the black - fur phenotype.

Answer:

Black Fur: \( 100\% \), White Fur: \( 0\% \)