Question

1. in rabbits, black fur (b) is dominant to white fur (b). a purebred (homozygous) black - furred male is bred with a female that has the recessive white fur.

Explanation:

Step1: Determine the genotypes

The purebred (homozygous) black - furred male has the genotype \(BB\). The female with recessive white fur has the genotype \(bb\).

Step2: Create the Punnett square

The male can only contribute \(B\) gametes. The female can only contribute \(b\) gametes.

	\(b\)	\(b\)
\(B\)	\(Bb\)	\(Bb\)

Step3: Calculate the probabilities

All offspring have the genotype \(Bb\). Since \(B\) (black fur) is dominant, all offspring will have black fur. The probability of black fur is \(\frac{4}{4}=100\%\), and the probability of white fur is \(\frac{0}{4} = 0\%\).

Answer:

Black Fur: \(100\%\), White Fur: \(0\%\)