you want to determine the concentration when 93 ml of a 2.03 m kf solution is diluted by adding 3920 ml $\text{h}_2\text{o}$.
$m_1 = 2.03\text{ m}$ $v_1 = 93\text{ ml}$
$m_2 = ?\text{ m}$ $v_2 = 4013\text{ ml}$
\m_1v_1 = m_2v_2\
what is the molarity of the diluted solution?
? m

Question

you want to determine the concentration when 93 ml of a 2.03 m kf solution is diluted by adding 3920 ml $\text{h}_2\text{o}$.
$m_1 = 2.03\text{ m}$ $v_1 = 93\text{ ml}$
$m_2 = ?\text{ m}$ $v_2 = 4013\text{ ml}$
\m_1v_1 = m_2v_2\
what is the molarity of the diluted solution?
 ?  m

Accepted Answer

{ "quality": "clear", "question_count": 1, "skills_matched": [ "step_cot", "blank_filling_formatter", "explain_then_answer", "quick" ], "needs_drawing": false, "concepts_used": [ "Dilution Equation", "Solution Concentration", "Dilution Calculations", "Total Dilution Volume" ], "new_concepts": [], "current_concepts": [ "Dilution Equation", "Solution Concentration", "Dilution Calculations", "Total Dilution Volume" ] } ## Identify the given parameters $$ \begin{aligned} M_1 &= 2.03\text{ M} \ V_1 &= 93\text{ mL} \ V_2 &= 93\text{ mL} + 3920\text{ mL} = 4013\text{ mL} \end{aligned} $$ ## Apply the dilution equation $$ \begin{aligned} M_1 V_1 &= M_2 V_2 \ M_2 &= \frac{M_1 V_1}{V_2} \end{aligned} $$ ## Calculate the final molarity $$ \begin{aligned} M_2 &= \frac{2.03\text{ M} \times 93\text{ mL}}{4013\text{ mL}} \ M_2 &\approx 0.047047\text{ M} \ M_2 &\approx 0.047\text{ M} \end{aligned} $$ You want to determine the concentration when $93\text{ mL}$ of a $2.03\text{ M}$ KF solution is diluted by adding $3920\text{ mL}$ $\text{H}_2\text{O}$. $M_1 = 2.03\text{ M}$ $V_1 = 93\text{ mL}$ $M_2 = ?\text{ M}$ $V_2 = 4013\text{ mL}$ $M_1V_1 = M_2V_2$ What is the molarity of the diluted solution? 0.047 M { "subject": "Natural Science", "question_type": "Fill-in-the-blank", "knowledge_point": [ "Natural Science", "Chemistry", "Solution Dilution" ] }

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QUESTION IMAGE

Question

Explanation:

Identify the given parameters

Apply the dilution equation

Calculate the final molarity

Answer: