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Question
you are given the following set of data: 10, 10, 10, 10, 9, 9, 8, 7, 10, 5, 10, 10 you calculate the mean to be 10, you know that your calculation must be incorrect because... a the mean will never equal the maximum unless the entire data set is uniform b the mean will never equal the mode c the mean will never equal the median
Step1: Analyze Option A
The mean is the average, calculated as the sum of all data points divided by the number of data points. The maximum value in the data set is 10, but there are other values (like 9, 8, 7, 5) that are less than 10. For the mean to equal the maximum (10), all data points would have to be 10 (a uniform data set with all values 10). Since our data set has values less than 10, the mean can't be 10 if the data isn't uniform. So if we calculated the mean as 10, we know the calculation is wrong because the mean will never equal the maximum unless the entire data set is uniform.
Step2: Analyze Option B
Let's check if mean can equal mode. First, find the mode (most frequent value, which is 10 here). Let's calculate the actual mean: sum of data \(= 10 + 10 + 10 + 10 + 9 + 8 + 7 + 10 + 5 + 10 + 10\) (wait, wait, let's count the number of data points. Wait, the data is: 10,10,10,10,9,8,7,10,5,10,10? Wait, let's count: let's list them: 10 (1), 10 (2), 10 (3), 10 (4), 9 (5), 8 (6), 7 (7), 10 (8), 5 (9), 10 (10), 10 (11). Wait, 11 data points? Wait, original data: "10,10,10,10,9,8,7,10,5,10,10" – that's 11 numbers. Sum: let's calculate: number of 10s: let's see, positions 1 - 4: 4, then position 8,10,11: so 4 + 3 = 7? Wait, 10 appears 7 times? Wait 10,10,10,10 (4), then 9,8,7,10 (5), 5,10 (6), 10 (7). So 7 tens, 1 nine, 1 eight, 1 seven, 1 five. Sum \(= 7\times10 + 9 + 8 + 7 + 5 = 70 + 29 = 99\). Mean \(= \frac{99}{11} = 9\). But mode is 10. But suppose we had a data set where mean equals mode. For example, data set [10,10,10], mean is 10, mode is 10. So mean can equal mode, so option B is wrong.
Step3: Analyze Option C
Mean can equal median. Let's take a simple data set: [10,10,10], mean is 10, median is 10. So mean can equal median, so option C is wrong.
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A. the mean will never equal the maximum unless the entire data set is uniform