Question

write formulas for the compounds formed from sr and each of the following polyatomic ions: $clo_4^-$, $so_4^{2 - }$, $po_4^{3 - }$.
express your answers as chemical formulas separated by commas.

Explanation:

Step1: Determine the charge of Sr ion

Strontium (Sr) is in Group 2 of the periodic table, so it forms \(Sr^{2 +}\) ion.

Step2: Apply the criss - cross rule for \(ClO_4^-\)

For \(Sr^{2+}\) and \(ClO_4^-\), using the criss - cross rule (swap the magnitudes of charges), we get \(Sr(ClO_4)_2\).

Step3: Apply the criss - cross rule for \(SO_4^{2 -}\)

For \(Sr^{2+}\) and \(SO_4^{2 -}\), since the charges are \(+ 2\) and \(-2\), the formula is \(SrSO_4\).

Step4: Apply the criss - cross rule for \(PO_4^{3 -}\)

For \(Sr^{2+}\) and \(PO_4^{3 -}\), using the criss - cross rule (swap the magnitudes of charges \(2\) and \(3\)), we get \(Sr_3(PO_4)_2\).

Answer:

\(Sr(ClO_4)_2,SrSO_4,Sr_3(PO_4)_2\)