Question

write the formula for the sodium ion.

• subscripts and superscripts are not supported in answer boxes so they are in normal script.

○ so₄²⁻ is written as so4^2-
○ na₂so₄ is written as na2so4

Explanation:

Step1: Analyze sodium's electron configuration

Sodium (Na) has an atomic number of 11. Its electron configuration is \(1s^{2}2s^{2}2p^{6}3s^{1}\). It loses one electron to achieve a stable noble - gas configuration (similar to neon, \(1s^{2}2s^{2}2p^{6}\)).

Step2: Determine the ion formula

When it loses one electron (\(e^{-}\)), the ion formed is \(Na^{+}\). According to the given format (subscripts and superscripts in normal script), it is written as \(Na^+\).

Answer:

\(Na^+\)