Question

write the electron configuration of an atom of the element highlighted in this outline of the periodic table:
hint: you do not need to know the name or symbol of the highlighted element!

Explanation:

Step1: Determine the number of electrons

The element is in the 3rd period. The noble gas before it is Ne (10 electrons). The element has \(10 + 4=14\) electrons.

Step2: Write the electron configuration

Using the Aufbau principle, the electron configuration is \(1s^{2}2s^{2}2p^{6}3s^{2}3p^{2}\)

Answer:

\(1s^{2}2s^{2}2p^{6}3s^{2}3p^{2}\)