Question

write the condensed (noble - gas) electron configuration of o.
for multi - digit superscripts or coefficients, use each number in succession.
he ne ar kr xe rn
1 2 3 4 5 6
s p d f

Explanation:

Step1: Determine the atomic number of oxygen

Oxygen has an atomic number of 8.

Step2: Identify the noble - gas core

The noble - gas core for oxygen is helium ([He]).

Step3: Determine the remaining electrons

After using the [He] core (which accounts for 2 electrons), there are \(8 - 2=6\) electrons left.

Step4: Distribute the remaining electrons

The remaining 6 electrons are distributed as \(2s^{2}2p^{4}\)

Answer:

$$ [\text{He}]2s^{2}2p^{4} $$