Question

write the chemical formula for chromium(iii) sulfide

Explanation:

Step1: Determine the ions

Chromium(III) has a charge of \(Cr^{3+}\), sulfide ion has a charge of \(S^{2 -}\).

Step2: Use the criss - cross method

To balance the charges, we take the absolute value of the charge of one ion as the subscript of the other ion. So for \(Cr^{3+}\) and \(S^{2 -}\), the formula is \(Cr_2S_3\).

Answer:

\(Cr_2S_3\)