Question

write the balanced net ionic equation for the reaction when copper(ii) sulfate and ammonium hydroxide are mixed in aqueous solution. if no reaction occurs, simply write only nr. be sure to include the proper phases for all species within the reaction.

Explanation:

Step1: Write the formulas of reactants and products

Copper(II) sulfate (\(CuSO_4\)) is in aqueous solution (\(CuSO_4(aq)\)), ammonium hydroxide (\(NH_4OH\)) is in aqueous solution (\(NH_4OH(aq)\)). The reaction between them forms copper(II) hydroxide (\(Cu(OH)_2\)) which is a precipitate (\(Cu(OH)_2(s)\)) and ammonium sulfate (\((NH_4)_2SO_4\)) which is in aqueous solution (\((NH_4)_2SO_4(aq)\)).
The overall ionic equation:
\(Cu^{2 +}(aq)+SO_4^{2 -}(aq)+NH_4^{+}(aq)+OH^{-}(aq)\to Cu(OH)_2(s)+NH_4^{+}(aq)+SO_4^{2 -}(aq)\)

Step2: Cancel out the spectator ions

The spectator ions are \(SO_4^{2 -}(aq)\) and \(NH_4^{+}(aq)\) (they appear on both sides of the equation unchanged).

Answer:

\(Cu^{2+}(aq)+2OH^{-}(aq)\to Cu(OH)_2(s)\)