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the work must of your highest quality. assessment therefore you need to…

Question

the work must of your highest quality. assessment therefore you need to show all your work and use rulers and/or graph paper where necessary. - you must hand in these assignment questions, otherwise it will not be marked. - round all your answers to the nearest hundredth, if necessary. - be sure to include units where required. arking scheme: question 1 2 3 4 5 total marks 6 6 7 5 6 e edmonton elks uses mathematics every day. they encounter a number of problems that can be lved using the concepts learned in math 10c. in this assignment you will use your knowledge of math c to help the team solve their problems. 1) on the outside of commonwealth stadium the edmonton elks would like to place a large, rectangular sign to reveal their new name and logo. the approximate area of the sign can be represented by the trinomial ( x^2 - 7x + 6 ). a) factor the area to find the binomials that represent the length and width of the sign. b) if ( x ) represents 14m, find the length and width of the sign, in metres. c) if the sign costs $60/m², calculate how much the team will have to pay. d) the team decided that they want the sign to be a square instead of a rectangle. state what gi an example of a trinomial that could represent the area. what do we call this type of trinomi e) if the area of the square sign is to be ( x^2 - kx + 625 ), find the binomial factor that would represent the side length of this area and determine the value of ( k ), if the trinomial is factor over the integers?

Explanation:

(a) - Factoring the Trinomial

Step 1: Identify \(a\), \(b\), \(c\)

For \(x^2 - 7x + 6\), \(a = 1\), \(b=-7\), \(c = 6\). We need two numbers that multiply to \(ac=6\) and add to \(b=-7\).

Step 2: Find the numbers

The numbers are \(-1\) and \(-6\) (since \((-1)\times(-6)=6\) and \(-1 + (-6)=-7\)).

Step 3: Factor the trinomial

Rewrite the middle term: \(x^2 - x - 6x + 6\). Group: \((x^2 - x)+(-6x + 6)=x(x - 1)-6(x - 1)\). Factor out \((x - 1)\): \((x - 1)(x - 6)\).

Step 1: Substitute \(x = 14\) into the factors

From part (a), the factors are \((x - 1)\) and \((x - 6)\).
For \(x - 1\): \(14 - 1 = 13\) m.
For \(x - 6\): \(14 - 6 = 8\) m.

Step 1: Calculate the area

Area = length \(\times\) width = \(13\times8 = 104\) \(m^2\).

Step 2: Calculate the cost

Cost = area \(\times\) cost per \(m^2\) = \(104\times60 = 6240\) dollars.

Answer:

\((x - 1)(x - 6)\)

Part (b) - Length and Width when \(x = 14\) m