Question

1. whiskers the cat weighs $2\frac{2}{3}$ kg. piglio weighs 4 kg. for each question, write a multiplication and a division equation, decide whether the answer is greater or less than 1, and then answer the question.

a. how many times as heavy as piglio is whiskers?

b. how many times as heavy as whiskers is piglio?

Explanation:

Part a

Step1: Define Variables and Equations

Let \( W = 2\frac{2}{3}=\frac{8}{3} \) kg (Whiskers' weight) and \( P = 4 \) kg (Piglio's weight). We want to find how many times \( W \) is of \( P \), so let the factor be \( x \). Then the multiplication equation is \( P\times x = W \), i.e., \( 4\times x=\frac{8}{3} \). The division equation is \( x = W\div P=\frac{8}{3}\div4 \).

Step2: Solve the Division Equation

Simplify \( \frac{8}{3}\div4=\frac{8}{3}\times\frac{1}{4}=\frac{2}{3} \). Since \( \frac{2}{3}< 1 \), the answer is less than 1.

Step3: Solve the Multiplication Equation

From \( 4\times x=\frac{8}{3} \), we get \( x = \frac{8}{3}\div4=\frac{2}{3} \) (same as division result).

Step1: Define Variables and Equations

Let \( W=\frac{8}{3} \) kg and \( P = 4 \) kg. We want to find how many times \( P \) is of \( W \), so let the factor be \( y \). The multiplication equation is \( W\times y=P \), i.e., \( \frac{8}{3}\times y = 4 \). The division equation is \( y=P\div W = 4\div\frac{8}{3} \).

Step2: Solve the Division Equation

Simplify \( 4\div\frac{8}{3}=4\times\frac{3}{8}=\frac{3}{2} \). Since \( \frac{3}{2}>1 \), the answer is greater than 1.

Step3: Solve the Multiplication Equation

From \( \frac{8}{3}\times y = 4 \), we get \( y = 4\div\frac{8}{3}=\frac{3}{2} \) (same as division result).

Answer:

Multiplication equation: \( 4\times x=\frac{8}{3} \); Division equation: \( \frac{8}{3}\div4 = x \); Answer is less than 1; Whiskers is \( \frac{2}{3} \) times as heavy as Piglio.

Part b