Question

which represents the ion formed when aluminum achieves a full valence shell? al^{5+} al^{5-} al^{3+} al^{3-} a b c d

Explanation:

Aluminum (\(Al\)) has an atomic number of \(13\). Its electron configuration is \(1s^{2}2s^{2}2p^{6}3s^{2}3p^{1}\). To achieve a full valence shell (similar to the noble gas neon with \(8\) electrons in the valence shell), it loses \(3\) electrons. When an atom loses electrons, it forms a positive ion (cation). The number of electrons lost is indicated by the positive charge. So, aluminum forms \(Al^{3 +}\) ion.

Answer:

C. \(Al^{3+}\)