Question

which pair does not represent the probabilities of complementary events?
\\(\frac{3}{7}\\) and \\(\frac{4}{7}\\)
0 and 1
16% and 84%
0.25 and 0.50

Explanation:

Step1: Recall the property of complementary events

For two complementary events \(A\) and \(A'\), \(P(A)+P(A') = 1\).

Step2: Check each pair

• Pair \(\frac{3}{7}\) and \(\frac{4}{7}\):

\(\frac{3}{7}+\frac{4}{7}=\frac{3 + 4}{7}=1\)

• Pair \(0\) and \(1\):

\(0 + 1=1\)

• Pair \(16\%\) and \(84\%\):

Convert percentages to decimals: \(0.16+0.84 = 1\)

• Pair \(0.25\) and \(0.50\):

\(0.25+0.50=0.75
eq1\)

Answer:

\(0.25\) and \(0.50\)