Question

which model shows that it was sunny \\(\frac{2}{3}\\) of the days in june?

Explanation:

Step1: Determine June's days

June has 30 days. We need to find which calendar has $\frac{2}{3}$ of 30 days marked as sunny.

Step2: Calculate sunny days

Calculate $\frac{2}{3} \times 30 = 20$ sunny days.

Step3: Count suns in each calendar

• First calendar: Count the suns. Let's count: Looking at the first calendar, the number of suns (sunny days) should be 20? Wait, let's recount. Wait, first calendar: Let's list the sun positions. Wait, maybe better to count each. Wait, first calendar: Let's see, the first calendar (left) has how many suns? Let's count: 3 (days 2,3), then 5 (day4? No, day4: no, day5: sun, day6: sun, day7: sun, day8: sun, day9: no, day10: sun; then day11: sun, day12: no, day13: sun, day14: sun, day15: sun, day16: sun, day17: no; day18: no, day19: sun, day20: sun, day21: sun, day22: sun, day23: sun, day24: no; day25: sun, day26: no, day27: no, day28: sun, day29: sun, day30: no. Wait, maybe I'm miscounting. Wait, alternatively, the second calendar: let's count. Second calendar (middle): days with sun: 5,6,7,21,22,23? No, that's too few. Third calendar (right): even fewer. Wait, no, wait the first calendar: let's do $\frac{2}{3}$ of 30 is 20. So first calendar: let's count the suns. Let's see, the first calendar (left) has suns on: 2,3,5,6,7,8,10,11,13,14,15,16,19,20,21,22,23,25,28,29. Wait, that's 20? Let's count: 2 (1), 3 (2), 5 (3), 6 (4), 7 (5), 8 (6), 10 (7), 11 (8), 13 (9), 14 (10), 15 (11), 16 (12), 19 (13), 20 (14), 21 (15), 22 (16), 23 (17), 25 (18), 28 (19), 29 (20). Yes! So the first (left) calendar has 20 sunny days, which is $\frac{2}{3}$ of 30. The middle has way less, the right has less. So the left calendar (first model) has 20 sunny days, which is $\frac{2}{3}$ of 30.

Answer:

The Left Graph (the first calendar model)