Question

which of the following statements accurately represents what is occurring in this equation?
6 cs + n₂ → 2 cs₃n
if 6 atoms of cs react with 1 molecule of n₂, they should produce 2 molecules of cs₃n.
6 moles of cs can react with 1 mole of n₂ to produce 2 moles of cs₃n.
if 6 atoms of cs react with 1 molecule of n₂, they should produce 1 molecule of cs₃n.
3 moles of cs can react with 0.5 moles of n₂ to produce 1 mole of cs₃n.
3.61 x 10²⁴ atoms of c will completely react with 6.02 x 10²³ molecules of n₂ to produce 2 moles of cs₃n.

Explanation:

Step1: Analyze the first option

In a chemical equation, the coefficients represent the ratio of moles or number of particles (atoms, molecules). The equation \(6Cs + N_2
ightarrow2Cs_3N\) means that for every 6 atoms of \(Cs\) and 1 molecule of \(N_2\), 2 molecules of \(Cs_3N\) are produced. So, the first option is correct.

Step2: Analyze the second option

According to the stoichiometry of the equation \(6Cs + N_2
ightarrow2Cs_3N\), the ratio of \(Cs:N_2:Cs_3N\) is \(6:1:2\) in terms of moles. So, 6 moles of \(Cs\) can react with 1 mole of \(N_2\) to produce 2 moles of \(Cs_3N\). This option is correct.

Step3: Analyze the third option

From the equation \(6Cs + N_2
ightarrow2Cs_3N\), when 6 atoms of \(Cs\) react with 1 molecule of \(N_2\), 2 molecules of \(Cs_3N\) are formed, not 1. So, this option is incorrect.

Step4: Analyze the fourth option

If we divide the coefficients of the equation \(6Cs + N_2
ightarrow2Cs_3N\) by 2, we get \(3Cs+0.5N_2
ightarrow1Cs_3N\). So, 3 moles of \(Cs\) can react with 0.5 moles of \(N_2\) to produce 1 mole of \(Cs_3N\). This option is correct.

Step5: Analyze the fifth option

First, calculate the number of moles of \(Cs\) using \(n=\frac{N}{N_A}\), where \(N = 3.61\times10^{24}\) and \(N_A=6.02\times 10^{23}\). \(n=\frac{3.61\times10^{24}}{6.02\times10^{23}} = 6\) moles of \(Cs\). Number of moles of \(N_2\) is \(n=\frac{6.02\times10^{23}}{6.02\times10^{23}}=1\) mole. According to the equation \(6Cs + N_2
ightarrow2Cs_3N\), 6 moles of \(Cs\) and 1 mole of \(N_2\) produce 2 moles of \(Cs_3N\). But the element in the reactant is \(Cs\) (cesium), not \(C\) (carbon). So, this option is incorrect.

Answer:

First option: If 6 atoms of Cs react with 1 molecule of \(N_2\), they should produce 2 molecules of \(Cs_3N\).
Second option: 6 moles of Cs can react with 1 mole of \(N_2\) to produce 2 moles of \(Cs_3N\).
Fourth option: 3 moles of Cs can react with 0.5 moles of \(N_2\) to produce 1 mole of \(Cs_3N\).