QUESTION IMAGE
Question
- which of the following is a rational number?
a. $\pi$
b. $\sqrt{2}$
c. $\frac{3}{5}$
d. $\sqrt{5}$
- the additive identity element for real numbers is:
a. 0
b. 1
c. $-1$
d. $\infty$
- what is the multiplicative inverse of 8?
a. 8
b. $\frac{1}{8}$
c. $-8$
d. 0
- which property is illustrated by the equation $5 + 7 = 7 + 5$?
a. associative property
b. commutative property
c. distributive property
d. identity property
- if $a = \\{1,2,3,4\\}$ and $b = \\{3,4,5,6\\}$, what is $a \cap b$?
a. $\\{1,2,3,4,5,6\\}$
b. $\\{3,4\\}$
c. $\\{1,2,5,6\\}$
d. $\emptyset$
- the symbol $\subseteq$ means:
a. proper subset
b. subset
c. union
d. intersection
- in a venn diagram, $a \cap b$ represents:
a. only in $a$
b. only in $b$
c. in both $a$ and $b$
d. outside both
- which of the following is irrational?
Question 1
Step1: Recall rational number definition
A rational number is a number that can be expressed as $\frac{p}{q}$, where $p$ and $q$ are integers and $q
eq0$.
Step2: Analyze each option
- Option A: $\pi$ is an irrational number (non - repeating, non - terminating decimal).
- Option B: $\sqrt{2}$ is irrational (cannot be expressed as a fraction of two integers).
- Option C: $\frac{3}{5}$ is in the form $\frac{p}{q}$ with $p = 3$, $q = 5$ (integers, $q
eq0$), so it is rational.
- Option D: $\sqrt{5}$ is irrational (cannot be expressed as a fraction of two integers).
Step1: Recall additive identity definition
The additive identity element of a set of numbers is an element which when added to any number in the set leaves the number unchanged.
Step2: Analyze each option
- Option A: For any real number $x$, $x + 0=x$. So 0 is the additive identity.
- Option B: $x + 1
eq x$ (unless $x = 0$), so 1 is not the additive identity.
- Option C: $x+( - 1)
eq x$ (unless $x = 1$), so - 1 is not the additive identity.
- Option D: $\infty$ is not a real number in the context of additive identity (and $x+\infty=\infty
eq x$ for finite $x$).
Step1: Recall multiplicative inverse definition
The multiplicative inverse of a non - zero number $a$ is a number $b$ such that $a\times b = 1$.
Step2: Find the multiplicative inverse of 8
Let the multiplicative inverse of 8 be $x$. Then $8\times x=1$. Solving for $x$, we get $x=\frac{1}{8}$.
- Option A: $8\times8 = 64
eq1$, so 8 is not the multiplicative inverse.
- Option B: $8\times\frac{1}{8}=1$, so $\frac{1}{8}$ is the multiplicative inverse.
- Option C: $8\times(-8)=-64
eq1$, so - 8 is not the multiplicative inverse.
- Option D: $8\times0 = 0
eq1$, so 0 is not the multiplicative inverse.
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C. $\frac{3}{5}$