Question

which of the following formulas represents manganese (iv) sulfide? mns₂ mns mn₂s₃ mn₂s

Explanation:

Step1: Determine the charge of manganese and sulfide ion

Manganese (IV) has a charge of \(Mn^{4+}\). Sulfide ion has a charge of \(S^{2 -}\).

Step2: Use the criss - cross method to find the formula

For ionic compounds, we use the criss - cross method. The charge of \(Mn^{4+}\) (4) becomes the subscript of \(S\), and the charge of \(S^{2 -}\) (2) becomes the subscript of \(Mn\). But we simplify the ratio. \(\frac{4}{2}=2\) for \(S\) and \(\frac{2}{2} = 1\) for \(Mn\). So the formula is \(MnS_{2}\).

Answer:

\(MnS_{2}\)