Question

which of the following compounds exhibits a linear molecular geometry? select two correct answers.
h₂o
ch₄
co₂
h₂s
bef₂

Explanation:

Step1: Analyze \(H_2O\)

The central atom \(O\) has \(2\) bonding pairs and \(2\) lone pairs. According to VSEPR theory, it has a bent geometry.

Step2: Analyze \(CH_4\)

The central atom \(C\) has \(4\) bonding pairs and \(0\) lone pairs. According to VSEPR theory, it has a tetrahedral geometry.

Step3: Analyze \(CO_2\)

The central atom \(C\) has \(2\) bonding pairs (double - bonds count as one region of electron density) and \(0\) lone pairs. According to VSEPR theory, it has a linear geometry.

Step4: Analyze \(H_2S\)

The central atom \(S\) has \(2\) bonding pairs and \(2\) lone pairs. According to VSEPR theory, it has a bent geometry.

Step5: Analyze \(BeF_2\)

The central atom \(Be\) has \(2\) bonding pairs and \(0\) lone pairs. According to VSEPR theory, it has a linear geometry.

Answer:

\(CO_2\), \(BeF_2\)