Question

when using a calorimeter, the initial temperature of a metal is 70.4°c. the initial temperature of the water is 23.6°c. at the end of the experiment, the final equilibrium temperature of the water is 29.8°c. what is the final temperature of the metal? °c what is the temperature change of the water? °c what is the temperature change of the metal? °c

Explanation:

Step1: Find the final temperature of the metal

In a calorimeter, at equilibrium, the final temperature of the metal is the same as the final temperature of the water.
So, the final temperature of the metal \(T_{metal - final}=29.8^{\circ}C\)

Step2: Calculate the temperature change of the water

The formula for temperature change is \(\Delta T=T_{final}-T_{initial}\)
For water, \(T_{initial - water}=23.6^{\circ}C\) and \(T_{final - water}=29.8^{\circ}C\)
\(\Delta T_{water}=29.8 - 23.6=6.2^{\circ}C\)

Step3: Calculate the temperature change of the metal

For metal, \(T_{initial - metal}=70.4^{\circ}C\) and \(T_{final - metal}=29.8^{\circ}C\)
Using the formula \(\Delta T=T_{final}-T_{initial}\)
\(\Delta T_{metal}=29.8 - 70.4=- 40.6^{\circ}C\)

Answer:

The final temperature of the metal: \(29.8^{\circ}C\)
The temperature change of the water: \(6.2^{\circ}C\)
The temperature change of the metal: \(-40.6^{\circ}C\)