Question

when testing with α = 0.05 you get p = 3.2 e - 6. your decision should be
reject ho, there is a
significant difference
reject ho, there is not
a significant difference
fail to reject ho, there
is not a significant
difference
accept ho, there is a
significant difference

Explanation:

Step1: Compare p - value and significance level

Given $\alpha = 0.05$ and $p=3.2\times10^{-6}=0.0000032$.
Since $p = 0.0000032<\alpha = 0.05$.

Step2: Make decision based on comparison

When $p<\alpha$, we reject the null hypothesis $H_0$. And when we reject $H_0$, it means there is a significant difference.

Answer:

Reject $H_0$, there is a significant difference.