Question

when a gas at 325 k and 767.0 mm hg changes in pressure to 810.0 mm hg, what is the new temperature? t = ? k

Explanation:

Step1: Apply Gay-Lussac's Law

$\frac{P_1}{T_1} = \frac{P_2}{T_2}$
Rearrange to solve for $T_2$: $T_2 = T_1 \times \frac{P_2}{P_1}$

Step2: Substitute values

$T_1 = 325\ \text{K}, P_1 = 767.0\ \text{mmHg}, P_2 = 810.0\ \text{mmHg}$
$T_2 = 325 \times \frac{810.0}{767.0}$

Step3: Calculate the result

$T_2 = 325 \times 1.05606 \approx 343\ \text{K}$

Answer:

343 K