Question

1. what is the specific heat capacity of mercury if it requires 167.1 j to change the temperature of 15.0 g of mercury from 25.00°c to 33.00°c?

Explanation:

Step1: Calculate the temperature change

The formula for temperature change is $\Delta T=T_{final}-T_{initial}$.
Here, $T_{initial} = 25.00^{\circ}C$ and $T_{final}=33.00^{\circ}C$.
So, $\Delta T=33.00 - 25.00=8.00^{\circ}C$.

Step2: Use the heat - transfer formula

The heat - transfer formula is $Q = mc\Delta T$, where $Q$ is the heat energy, $m$ is the mass, $c$ is the specific heat capacity, and $\Delta T$ is the temperature change.
We need to solve for $c$, so we can rewrite the formula as $c=\frac{Q}{m\Delta T}$.
Given that $Q = 167.1\ J$, $m = 15.0\ g$, and $\Delta T=8.00^{\circ}C$.
Substitute the values into the formula: $c=\frac{167.1}{15.0\times8.00}$.
First, calculate the denominator: $15.0\times8.00 = 120$.
Then, $c=\frac{167.1}{120}=1.3925\ J/(g\cdot^{\circ}C)$.

Answer:

$1.39\ J/(g\cdot^{\circ}C)$ (rounded to three significant figures)