Question

if $n(a)=41$, $n(b)=22$, and $n(acap b)=6$, then what is $n(acup b)$? provide your answer below:

Explanation:

Step1: Recall the formula for \(n(A\cup B)\)

The formula is \(n(A\cup B)=n(A)+n(B)-n(A\cap B)\)

Step2: Substitute the given values

Substitute \(n(A) = 41\), \(n(B)=22\), and \(n(A\cap B)=6\) into the formula:
\(n(A\cup B)=41 + 22-6\)

Step3: Calculate the result

\(41+22 = 63\), then \(63-6=57\)

Answer:

57