Question

what is the pressure when a gas at 215 torr in a 51.0 ml vessel is reduced to a volume of 18.5 ml? p = ? torr assume that the number of moles and the temperature remain constant.

Explanation:

Step1: Recall Boyle's Law formula

$P_1V_1 = P_2V_2$
Given: $P_1=215$ torr, $V_1=51.0$ mL, $V_2=18.5$ mL
Solve for $P_2$: $P_2 = \frac{P_1V_1}{V_2}$

Step2: Substitute values into formula

$P_2 = \frac{215 \times 51.0}{18.5}$

Step3: Calculate the result

$P_2 = \frac{10965}{18.5} \approx 593$ torr

Answer:

593 torr