Question

1. what is the percent composition of na₂co₃?% na =% c =% o =

Explanation:

Step1: Calculate molar mass of \(Na_2CO_3\)

Atomic masses: \(Na = 22.99\space g/mol\), \(C = 12.01\space g/mol\), \(O=16.00\space g/mol\)
Molar mass of \(Na_2CO_3=2\times22.99 + 12.01+3\times16.00\)
\(=45.98 + 12.01+48.00\)
\(=105.99\space g/mol\)

Step2: Calculate \(\%\text{Na}\)

Mass of \(Na\) in \(Na_2CO_3 = 2\times22.99 = 45.98\space g\)
\(\%\text{Na}=\frac{45.98}{105.99}\times 100\%\)
\(\%\text{Na}\approx43.4\%\)

Step3: Calculate \(\%\text{C}\)

Mass of \(C\) in \(Na_2CO_3=12.01\space g\)
\(\%\text{C}=\frac{12.01}{105.99}\times 100\%\)
\(\%\text{C}\approx11.3\%\)

Step4: Calculate \(\%\text{O}\)

Mass of \(O\) in \(Na_2CO_3 = 3\times16.00=48.00\space g\)
\(\%\text{O}=\frac{48.00}{105.99}\times 100\%\)
\(\%\text{O}\approx45.3\%\)

Answer:

\(\%\text{Na}\approx43.4\%\), \(\%\text{C}\approx11.3\%\), \(\%\text{O}\approx45.3\%\)