Question

what is the oxidation state of zinc in zn(oh)4^2-?
0
4+
1+
2+

Explanation:

Step1: Set up the equation

Let the oxidation state of \(Zn\) be \(x\). The oxidation state of \(OH^-\) is \(- 1\). The overall charge of the complex \(Zn(OH)_4^{2 -}\) is \(-2\). So, we have the equation \(x+4\times(-1)=-2\).

Step2: Solve the equation

$$
LATEXBLOCK0
$$

Answer:

\(2+\) (the fourth option)